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How to search and sum the total size of files per year?

PPape
Contributor

Hi Guys,

i wrote a script that reads the MetaData of Files in an NTFS Filesystem (like Creation Date, Last Access Date, Size etc.)

I got the output in Splunk and can do things like see how many Files where added per year. (I get this from the Creation Date)

index="fileindex" | eval cdt = strftime(strptime(CreationDate,"%d.%m.%Y %H:%M:%S"),"%Y") | stats count by cdt

But I want to know how big those files in Sum are... per Year.

So now I have an output like:
Year, Number of Files

And I want to have:
Year, Number of Files, Size of the Files

Can you please help? I have no clue how to manage this.

Thanks in advance!

Tags (4)
1 Solution

MuS
Legend

Hi PPape,

try something like this:

index="fileindex" 
| eval cdt = strftime(strptime(CreationDate,"%d.%m.%Y %H:%M:%S"),"%Y") 
| stats sum(eval(size/1024/1024)) AS mySize_in_Mb count by cdt

hope this helps ...

cheers, MuS

View solution in original post

MuS
Legend

Hi PPape,

try something like this:

index="fileindex" 
| eval cdt = strftime(strptime(CreationDate,"%d.%m.%Y %H:%M:%S"),"%Y") 
| stats sum(eval(size/1024/1024)) AS mySize_in_Mb count by cdt

hope this helps ...

cheers, MuS

PPape
Contributor

This is exactly what i needed! Thank You very much!

0 Karma

PPape
Contributor

http://pastebin.com/U7edkq2v here is a small sample.
Yes i have a Field Size (It's the File Size in Byte)

0 Karma

MuS
Legend

Well, do you have the size of the files in your index=fileindex? If so please provide some samples....

0 Karma
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