I am using the following:
eval link=http_referrer+uri_path | top link
and I get
http://www.foxnews.com//static/includes/partners/dma/520.html
I want to remove the double "//" and replace it with just one "/"
I cannot get my regex to work???
... | rex mode=sed field=link "s/\/\//\//"
|eval http_referrer = substr(http_referrer, 1, len(http_referrer)-1)| eval link=http_referrer+uri_path |