Splunk Search

How to extract the file name from a file path using rex in a search?

twh1
Communicator

I am getting the file path in my search result. When I am displaying it in dashboard with chart, I need to only extract the file name, not the complete path.

Current output:
/app/wlprd11g/instances/csweb1020/logs/csweb1020_access.log
/app/wlprd11g/instances/csweb1021/logs/csweb1021_access.log
/app/wlprd11g/instances/csweb1022/logs/csweb1022_access.log
/app/wlprd11g/instances/csweb1023/logs/csweb1023_access.log

Desired output:
csweb1020_access.log
csweb1021_access.log
csweb1022_access.log
csweb1023_access.log

0 Karma
1 Solution

twh1
Communicator

I used substr function and got the expected result.

... | eval source=substr(source,40)

View solution in original post

0 Karma

twh1
Communicator

I used substr function and got the expected result.

... | eval source=substr(source,40)

0 Karma

richgalloway
SplunkTrust
SplunkTrust

Try this.

... | rex "(?:\/?.+\/)*(.+?)$" | ...
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If this reply helps you, Karma would be appreciated.
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